12x^2-38x-40=0

Solution for 12x^2-38x-40=0 equation:

12x^2-38x-40=0

a = 12; b = -38; c = -40;
Δ = b2-4ac
Δ = -382-4·12·(-40)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-58}{2*12}=\frac{-20}{24}
=-5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+58}{2*12}=\frac{96}{24}
=4
$